For a triangle ABC, let p = BC, q = CA and r = BA. If | p| = 2 3, | q| = 2 and = 1 3, where is the angle between p and q, then | p ( q - 3 r)|2 + 3| r|2 is equal to :
- 200
- 220
- 410
- 340
Answer
(1) 200
Solution
r = BA = BC + CA = p + q
p q = 2 3 2 1 3 = 4
| r|2 = | p|2 + | q|2 + 2 p q = 12 + 4 + 8 = 24
q - 3 r = q - 3 p - 3 q = -3 p - 2 q
p ( q - 3 r) = -2( p q) ( p p = 0)
| p q|2 = | p|2| q|2 - ( p q)2 = 48 - 16 = 32
| p ( q - 3 r)|2 = 4 32 = 128
required value = 128 + 3 24 = 200
Answer: (1)