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Chemical Bonding and Molecular Structure · Question 1

JEE Advanced 2026 Paper 1MCQMedium📈 Topic in 17% papers+4−1
1

The correct order of dipole moments for the given species is

  1. BF3 = NH4+ < NF3 < NH3
  2. BF3 < NH4+ < NF3 < NH3
  3. NH4+ < BF3 < NH3 < NF3
  4. BF3 < NH4+ < NH3 < NF3

Answer

(2) BF3 < NH4+ < NF3 < NH3

Solution

BF3: trigonal planar and symmetric, so the bond moments cancel exactly. = 0, the lowest.

NH4+: tetrahedral, so its bond moments also cancel. As a charged species, its dipole moment is not defined independent of origin; the official key ranks it above BF3.

NH3: the lone-pair moment and the N–H bond moments (N more electronegative) point the same way, giving = 1.47 D.

NF3: the N–F bond moments oppose the lone-pair moment, giving = 0.23 D. So NF3 < NH3.

Order: BF3 < NH4+ < NF3 < NH3

Answer: (B)

JEE Advanced 2026 Paper 1

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2

Consider the following species: SOCl2, XeOF4, ClF3, ClF5, XeF5+, SO32-, XeF3+, SF4 List-I contains different molecular shapes and List-II contains total number of species with the same molecular shapes from the given species. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.

  1. P → 1; Q → 2; R → 5; S → 3
  2. P → 5; Q → 4; R → 2; S → 3
  3. P → 3; Q → 2; R → 1; S → 4
  4. P → 1; Q → 3; R → 5; S → 4
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3

The correct order of ONO bond angle in the given species is

  1. NO2+<NO2<NO3-<NO2-
  2. NO2-<NO3-<NO2<NO2+
  3. NO3-<NO2-<NO2<NO2+
  4. NO2-<NO3-<NO2+<NO2
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4

Regarding the molecular orbital (MO) energy levels for homonuclear diatomic molecules, the INCORRECT statement(s) is(are)

  1. Bond order of Ne2 is zero.
  2. The highest occupied molecular orbital (HOMO) of F2 is σ-type.
  3. Bond energy of O2+ is smaller than the bond energy of O2.
  4. Bond length of Li2 is larger than the bond length of B2.
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5

The option(s) in which at least three molecules follow Octet Rule is(are)

  1. CO2, C2H4, NO and HCl
  2. NO2, O3, HCl and H2SO4
  3. BCl3, NO, NO2 and H2SO4
  4. CO2, BCl3, O3 and C2H4
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