Equilibrium · Question 20

The pKb of dimethyl amine and pKa of acetic acid are 3.27 and 4.77 respectively at T (K). The correct option for the pH of dimethyl ammonium acetate solution is :

1. 6.25
2. 8.50
3. 5.50
4. 7.75

Hydrolysis of sucrose is given by the following reaction. Sucrose + H2O Glucose + Fructose If the equilibrium constant (Kc) is 2 1013 at 300 K, the value of r G at the same temperature will be :

1. 8.314 J mol-1 K-1 300 K (2 1013)
2. 8.314 J mol-1 K-1 300 K (3 1013)
3. -8.314 J mol-1 K-1 300 K (4 1013)
4. -8.314 J mol-1 K-1 300 K (2 1013)

Find out the solubility of Ni(OH)2 in 0.1 M NaOH. Given that the ionic product of Ni(OH)2 is 2 10-15.

1. 2 10-8 M
2. 1 10-13 M
3. 1 108 M
4. 2 10-13 M

Conjugate base for Brönsted acids H2O and HF are :

1. OH- and F-, respectively
2. H3O+ and H2F+, respectively
3. OH- and H2F+, respectively
4. H3O+ and F-, respectively

pH of a saturated solution of Ca(OH)2 is 9. The solubility product ( Ksp) of Ca(OH)2 is :

1. 0.125 10-15
2. 0.5 10-10
3. 0.5 10-15
4. 0.25 10-10

Which will make basic buffer?

1. 100 mL of 0.1 M HCl + 200 mL of 0.1 M NH4OH
2. 100 mL of 0.1 M HCl + 100 mL of 0.1 M NH4OH
3. 50 mL of 0.1 M NaOH + 25 mL of 0.1 M CH3COOH
4. 100 mL of 0.1 M CH3COOH + 100 mL of 0.1 M NaOH

Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations : pH of which one of them will be equal to 1?

1. B
2. A
3. D
4. C

The solubility of BaSO4 in water is 2.42 10-3 g L-1 at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4 = 233 g mol-1)

1. 1.08 10-10 mol2 L-2
2. 1.08 10-12 mol2 L-2
3. 1.08 10-14 mol2 L-2
4. 1.08 10-8 mol2 L-2

Which one of the following conditions will favour maximum formation of the product in the reaction A2(g) + B2(g) X2(g), rH = -X kJ ?

1. Low temperature and high pressure
2. Low temperature and low pressure
3. High temperature and high pressure
4. High temperature and low pressure

The equilibrium constants of the following are N2 + 3H2 2NH3; K1 N2 + O2 2NO; K2 H2 + 12O2 H2O; K3 The equilibrium constant (K) of the reaction : 2NH3 + 52O2 2NO + 3H2O will be

1. K2K33/K1
2. K2K3/K1
3. K23K3/K1
4. K1K33/K2