The rate constants k1 and k2 for two different reactions are 1016 e-2000/T and 1015 e-1000/T, respectively. The temperature at which k1 = k2 is
- 2000 K
- 10002.303 K
- 1000 K
- 20002.303 K
Answer
(2) 10002.303 K
Solution
k1 = k2
1016 e-2000/T = 1015 e-1000/T
10 = e2000/T - 1000/T = e1000/T
10 = 1000T
2.303 = 1000T
T = 10002.303 K
Answer: (2)