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Continuity and Differentiability

JEE Main 2024 (Online) 9th April Morning ShiftNumericalMedium📈 Topic in 34% papers+4
Ques. 1JEE Main 2024, 9 April (Morning Shift)

Let f : (0, ) R be a function given by f(x) = cases ( 87 ) 8x 7x, & 0 < x < 2 \ a - 8, & x = 2 \ (1 + | x|) ba| x|, & 2 < x < cases where a, b Z. If f is continuous at x = 2, then a2 + b2 is equal to .

Answer

81

Solution

Left-hand limit: put x = 2 - h (h 0+); then 8x = (4 - 8h) = - 8h and 7x = ( 7 2 - 7h ) = 7h

So 8x 7x = - 8h 7h 0

Hence LHL = ( 87 )0 = 1.

Continuity gives a - 8 = 1, so a = 9.

Right-hand limit: put x = 2 + h; then | x| = h and | x| = h

Since h = 1 h and (1 + t) 1t e as t 0:

RHL = h 0 [(1 + h) 1 h ] b9 = e b9

Since RHL = 1, e b9 = 1 gives b = 0. Therefore a2 + b2 = 81 + 0 = 81.

Answer: 81

Keep practising — Continuity and Differentiability

Ques. 2JEE Main 2024, 9 April (Evening Shift)

If e y = 3 -1x, then (1 - x2)y'' - xy' at x = 12 is equal to

  1. 9e /2
  2. 9e /6
  3. 3e /2
  4. 3e /6
Ques. 3JEE Main 2024, 8 April (Evening Shift)

For a, b > 0, let f(x) = cases ((a + 1)x) + b xx, & x < 0 \ 3, & x = 0 \ ax + b2x2 - axb a x x, & x > 0 cases be a continuous function at x = 0. Then ba is equal to :

  1. 4
  2. 5
  3. 8
  4. 6
Ques. 4JEE Main 2024, 6 April (Morning Shift)

If f(x) = cases x3 ( 1x ), & x 0 \ 0, & x = 0 cases, then

  1. f''(0) = 0
  2. f''(0) = 1
  3. f'' ( 2 ) = 24 - 22
  4. f'' ( 2 ) = 12 - 22
Ques. 5JEE Main 2024, 6 April (Morning Shift)

Let f : (- , ) - \0\ R be a differentiable function such that f'(1) = a a2 f ( 1a ). Then a a(a + 1)2 -1 ( 1a ) + a2 - 2 e a is equal to

  1. 52 + 8
  2. 38 + 4
  3. 34 + 8
  4. 32 + 4
Ques. 6JEE Main 2024, 6 April (Evening Shift)

Suppose for a differentiable function h, h(0) = 0, h(1) = 1 and h'(0) = h'(1) = 2. If g(x) = h (ex )eh(x), then g'(0) is equal to:

  1. 4
  2. 5
  3. 3
  4. 8
Ques. 7JEE Main 2024, 6 April (Evening Shift)

Let [t] denote the greatest integer less than or equal to t. Let f : [0, ) R be a function defined by f(x) = [ x2 + 3 ] - [ x]. Let S be the set of all points in the interval [0, 8] at which f is not continuous. Then a S a is equal to .

Ques. 8JEE Main 2024, 5 April (Morning Shift)

Let f(x) = x5 + 2x3 + 3x + 1, x R, and g(x) be a function such that g(f(x)) = x for all x R. Then g(7)g'(7) is equal to :

  1. 42
  2. 7
  3. 1
  4. 14
Ques. 9JEE Main 2024, 5 April (Morning Shift)

If the function f(x) = 3x + x - 3xx3, x R, is continuous at x = 0, then f(0) is equal to :

  1. 4
  2. -2
  3. -4
  4. 2
Ques. 10JEE Main 2024, 5 April (Evening Shift)

If y( ) = 2 + 2 3 + 4 2 + 5 + 2, then at = 2, y'' + y' + y is equal to :

  1. 12
  2. 1
  3. 32
  4. 2
Ques. 11JEE Main 2024, 5 April (Evening Shift)

Let f : [-1, 2] R be given by f(x) = 2x2 + x + [x2 ] - [x], where [t] denotes the greatest integer less than or equal to t. The number of points, where f is not continuous, is :

  1. 5
  2. 6
  3. 4
  4. 3

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