If y( ) = 2 + 2 3 + 4 2 + 5 + 2, then at = 2, y'' + y' + y is equal to :
- 12
- 1
- 32
- 2
Answer
(4) 2
Solution
Put c = : Nr = 2c2 + 2c - 1
Dr = (4c3 - 3c) + 4(2c2 - 1) + 5c + 2 = 4c3 + 8c2 + 2c - 2 = (2c2 + 2c - 1)(2c + 2)
y = 12(1 + )
y' = 2(1 + )2, y'' = 2(1 + )2 + 2 (1 + )3
At = 2 ( = 0, = 1): y = 12, y' = 12, y'' = 1
y'' + y' + y = 2
Answer: (4)