A satellite revolving around a planet in stationary orbit has time period 6 hours. The mass of planet is one-fourth the mass of earth. The radius of orbit of the satellite is : (Given: Radius of geo-stationary orbit for earth is 4.2 104 km)
- 1.68 105 km
- 1.4 104 km
- 8.4 104 km
- 1.05 104 km
Answer
(4) 1.05 104 km
Solution
Kepler's third law: T2 = 4 2 r3GM r3 MT2
Geostationary orbit of earth: Te = 24 h, re = 4.2 104 km
r3re3 = MMe ( TTe )2 = 14 ( 624 )2 = 164
r = re4 = 4.2 1044
= 1.05 104 km
Answer: (4)