Two tuning forks A and B are sounded together giving rise to 8 beats in 2 s. When fork A is loaded with wax, the beat frequency is reduced to 4 beats in 2 s. If the original frequency of tuning fork B is 380 Hz then original frequency of tuning fork A is Hz.
Answer
384
Solution
Initial beat frequency = 82 = 4 Hz fA = 380 4 = 384 Hz or 376 Hz
Loading A with wax decreases fA. New beat frequency = 42 = 2 Hz (decreased).
If fA = 384 Hz: a lower fA comes closer to 380 Hz, so the beat frequency decreases (consistent).
If fA = 376 Hz: a lower fA moves away from 380 Hz, so the beat frequency would increase (not possible).
fA = 384 Hz
Answer: 384