In an open organ pipe 3 and 6 are 3rd and 6th harmonic frequencies, respectively. If 6 - 3 = 2200 Hz then length of the pipe is mm. (Take velocity of sound in air is 330 m/s.)
- 200
- 225
- 275
- 250
Answer
(2) 225
Solution
For an open organ pipe, n = nv2L (n = 1, 2, 3, )
6 - 3 = (6 - 3)v2L = 3v2L = 2200
L = 3 3302 2200 = 0.225 m
L = 225 mm
Answer: (2)