0 x (16 ( x2 ) 3 ( x2 ) ) is equal to :
- 3 32
- 3 3
- 4 3
- 6 3
Answer
(2) 3 3
Solution
Let t= x2; 0 x 0 t 2
g(t)=16 t 3t
g'(t)=16 ( 4t-3 2t 2t )=16 2t ( 2t-3 2t )
g'(t)=0 in (0, 2 ) 2t= 13 t= 6
g ( 6 )=16 12 ( 32 )3=16 12 3 38=3 3
End values: g(0)=0, g ( 2 )=0
maximum value =3 3 (at x= 3)
Answer: (2)