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Integrals · Question 37

JEE Main 2025 (Online) 7th April Evening ShiftNumericalMedium📈 Topic in 23% papers+4
1

If ( 1x + 1x3 ) ( [23]3x-24 + x-26 ) dx = - 3( + 1) (3x + x ) + 1 + C, x > 0, ( , , Z), where C is the constant of integration, then + + is equal to .

Answer

19

Solution

[23]3x-24 + x-26 = [23]x-23 (3x-1 + x-3 ) = 1x ( 3x + 1x3 ) 123 (as x > 0)

I = ( 1x2 + 1x4 ) ( 3x + 1x3 ) 123 dx

Put u = 3x + 1x3

du = (- 3x2 - 3x4 ) dx = -3 ( 1x2 + 1x4 ) dx

I = - 13 u 123 du = - 13 2324 u 2423 + C

= - 233(24) (3x-1 + x-3 ) 2423 + C

Comparing: = 23, = -1, = -3

+ + = 23 - 1 - 3 = 19

Answer: 19

JEE Main 2025 (Online) 7th April Evening Shift

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2

The value of -11 (1 + |x| - x ) ex + ( |x| - x ) e-xex + e-x dx is equal to

  1. 1 + 2 23
  2. 1 - 2 23
  3. 2 + 2 23
  4. 3 - 2 23
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3

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  1. 0
  2. 10
  3. 1
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4

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7

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  1. 2 2
  2. 4 2
  3. 2
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8

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  1. 27
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  3. 24
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10

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  1. 2 - 2 - e(1 + 2)
  2. 2 + 2 + e(1 + 2)
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11

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  1. 3 4
  2. 4 3
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