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Integrals · Question 38

JEE Main 2025 (Online) 4th April Morning ShiftMCQMedium📈 Topic in 71% papers+4−1
1

The value of -11 (1 + |x| - x ) ex + ( |x| - x ) e-xex + e-x dx is equal to

  1. 1 + 2 23
  2. 1 - 2 23
  3. 2 + 2 23
  4. 3 - 2 23

Answer

(1) 1 + 2 23

Solution

Numerator = ex + |x| - x (ex + e-x)

⇒ I = -11 exex + e-x dx + -11 |x| - x dx = I1 + I2

I1: using -aa g(x) dx = -aa g(-x) dx,

2I1 = -11 ex + e-xex + e-x dx = 2 ⇒ I1 = 1

I2: for x 0, |x| - x = 0; for x < 0, |x| - x = -2x

⇒ I2 = -10 -2x dx = 2 01 t dt (put x = -t)

= 2 23 = 2 23

∴ I = 1 + 2 23

Answer: (1)

JEE Main 2025 (Online) 4th April Morning Shift

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2

Let f(x)+2f ( 1x )=x2+5 and 2g(x)-3g ( 12 )=x, x>0. If = 12 f(x) dx, and = 12 g(x) dx, then the value of 9 + is :

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3

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4

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5

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JEE Main 2025 (Online) 3rd April Morning Shift
6

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  1. 2 2
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7

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8

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  1. 27
  2. 18
  3. 24
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JEE Main 2025 (Online) 2nd April Evening Shift
9

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  1. 2 - 2 - e(1 + 2)
  2. 2 + 2 + e(1 + 2)
  3. 2 + 2 - e(1 + 2)
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10

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  1. 3 4
  2. 4 3
  3. 6 43
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11

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  2. 100
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