The pH of a solution obtained by mixing 5 mL of 0.1 M NH4OH solution with 250 mL of 0.1 M NH4Cl solution is 10-2. (Nearest integer) Given: pKb(NH4OH) = 4.74 2 = 0.30 3 = 0.48 5 = 0.70
Answer
756
Solution
NH4OH + NH4Cl = basic buffer (both in the same total volume, so the mole ratio can be used).
mmol of NH4OH = 5 × 0.1 = 0.5; mmol of NH4Cl = 250 × 0.1 = 25
pOH = pKb + [salt][base]
= 4.74 + 250.5 = 4.74 + 50
50 = 100 - 2 = 2 - 0.30 = 1.70
⇒ pOH = 4.74 + 1.70 = 6.44
⇒ pH = 14 − 6.44 = 7.56 = 756 × 10-2
Answer: 756