Consider a weak base 'B' of pKb = 5.699. 'x' mL of 0.02 M HCl and 'y' mL of 0.02 M weak base 'B' are mixed to make 100 mL of a buffer of pH 9 at 25 . The values of 'x' and 'y' respectively are : [Given : 2 = 0.3010, 3 = 0.4771, 5 = 0.699]
- arraycc x & y \ 42.7 & 57.3 array
- arraycc x & y \ 14.3 & 85.7 array
- arraycc x & y \ 85.7 & 14.3 array
- arraycc x & y \ 11.1 & 88.9 array
Answer
(2) arraycc x & y \ 14.3 & 85.7 array
Solution
pH = 9 pOH = 14 − 9 = 5
HCl neutralises part of the base: B + HCl BH+Cl-
mmol of BH+ = 0.02x ; mmol of B left = 0.02y − 0.02x = 0.02(y − x)
Henderson equation for a basic buffer: pOH = pKb + [BH+][B]
5 = 5.699 + xy - x
xy - x = -0.699 = - 5
y - xx = 5 y = 6x
Total volume: x + y = 100 7x = 100
x = 14.3 mL and y = 85.7 mL
Answer: (2)