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Equilibrium · Question 21

JEE Main 2026 (Online) 24th January Evening ShiftMCQMedium📈 Topic in 19% papers+4−1
1

Consider the following gaseous equilibrium in a closed container of volume 'V' at T(K). P2(g) + Q2(g) 2PQ(g) 2 moles each of P2(g), Q2(g) and PQ(g) are present at equilibrium. Now one mole each of 'P2' and 'Q2' are added to the equilibrium keeping the temperature at T(K). The number of moles of P2, Q2 and PQ at the new equilibrium, respectively, are

  1. 2.56, 1.62, 2.24
  2. 2.67, 2.67, 2.67
  3. 1.21, 2.24, 1.56
  4. 1.66, 1.66, 1.66

Answer

(2) 2.67, 2.67, 2.67

Solution

Kc = [PQ]2[P2][Q2] = (2/V)2(2/V)(2/V) = 1

After adding 1 mol each: P2 = 3, Q2 = 3, PQ = 2 mol

Qc = 223 3 = 49 < Kc reaction moves forward.

Let x mol of P2 react: P2 = 3 - x, Q2 = 3 - x, PQ = 2 + 2x

(2 + 2x)2(3 - x)2 = 1 ( ng = 0, V cancels)

2 + 2x = 3 - x

x = 13

P2 = Q2 = 3 - 13 = 2.67 mol; PQ = 2 + 23 = 2.67 mol

Answer: (2)

JEE Main 2026 (Online) 24th January Evening Shift

Keep practising — Equilibrium

2

Consider the general reaction given below at 400 K x A(g) y B(g). The values of Kp and Kc are studied under the same condition of temperature but variation in x and y. (i) Kp = 85.87 and Kc = 2.586 appropriate units (ii) Kp = 0.862 and Kc = 28.62 appropriate units The values of x and y in (i) and (ii) respectively are :

  1. array|c|c| (i) & (ii) \ 1,2 & 2,1 \ array
  2. array|c|c| (i) & (ii) \ 1,3 & 2,1 \ array
  3. array|c|c| (i) & (ii) \ 3,1 & 3,1 \ array
  4. array|c|c| (i) & (ii) \ 4,1 & 4,1 \ array
JEE Main 2026 (Online) 23rd January Morning Shift
3

For the following gas phase equilibrium reaction at constant temperature, NH3(g) 1/2 N2(g) + 3/2 H2(g) if the total pressure is 3 atm and the pressure equilibrium constant (Kp) is 9 atm, then the degree of dissociation is given as (x 10-2 )-1/2. The value of x is . (nearest integer)

JEE Main 2026 (Online) 23rd January Morning Shift
4

X2(g) + Y2(g) 2Z(g) X2(g) and Y2(g) are added to a 1 L flask and it is found that the system attains the above equilibrium at T(K) with the number of moles of X2(g), Y2(g) and Z(g) being 3, 3 and 9 mol respectively (equilibrium moles). Under this condition of equilibrium, 10 mol of Z(g) is added to the flask and the temperature is maintained at T(K). Then the number of moles of Z(g) in the flask when the new equilibrium is established is . (Nearest integer)

JEE Main 2026 (Online) 23rd January Evening Shift
5

Dissociation of a gas A2 takes place according to the following chemical reaction. At equilibrium, the total pressure is 1 bar at 300 K. A2(g) 2A(g) The standard Gibbs energy of formation of the involved substances has been provided below: arraycc Substance & Gf /kJ mol-1 \ A2 & -100.00 \ A & -50.832 array The degree of dissociation of A2(g) is given by (x 10-2)1/2 where x = . (Nearest integer). [ Given : R = 8 J mol-1 K-1, 2 = 0.3010, 3 = 0.48 ] Assume degree of dissociation is not negligible.

JEE Main 2026 (Online) 22nd January Morning Shift
6

Which of the following mixture gives a buffer solution with pH = 9.25 ? Given : pKb (NH4OH) = 4.75

  1. 0.5 M NH4OH (0.2 L) + 0.2 M HCl (0.5 L)
  2. 0.2 M NH4OH (0.5 L) + 0.1 M HCl (0.5 L)
  3. 0.2 M NH4OH (0.4 L) + 0.1 M HCl (1 L)
  4. 0.4 M NH4OH (1 L) + 0.1 M HCl (1 L)
JEE Main 2026 (Online) 22nd January Evening Shift
7

For the reaction, N2O4 2NO2, graph is plotted as shown below. Identify correct statements. [figure] Choose the correct answer from the options given below :

  1. C and E only
  2. D and E only
  3. A and D only
  4. B and C only
JEE Main 2026 (Online) 21st January Morning Shift
8

The first and second ionization constants of H2X are 2.5 10-8 and 1.0 10-13 respectively. The concentration of X2- in 0.1 M H2X solution is 10-15 M. (Nearest Integer)

JEE Main 2026 (Online) 21st January Evening Shift
9

The equilibrium constant for decomposition of H2O(g) H2O(g) H2(g) + 12O2(g); G = 92.34 kJ mol-1 is 8.0 10-3 at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation ( ) of water is 10-2 (nearest integer value). [Assume is negligible with respect to 1]

JEE Main 2025 (Online) 8th April Evening Shift
10

An aqueous solution of HCl with pH 1.0 is diluted by adding equal volume of water (ignoring dissociation of water). The pH of HCl solution would (Given 2 = 0.30)

  1. increase to 1.3
  2. reduce to 0.5
  3. increase to 2
  4. remain same
JEE Main 2025 (Online) 7th April Morning Shift
11

One litre buffer solution was prepared by adding 0.10 mol each of NH3 and NH4Cl in deionised water. The change in pH on addition of 0.05 mol of HCl to the above solution is 10-2. (Nearest integer) Given : pKb of NH3 = 4.745 and 10 3 = 0.477

JEE Main 2025 (Online) 7th April Evening Shift

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