Consider the following volume−temperature (V−T) diagram for the expansion of 5 moles of an ideal monoatomic gas. [figure] Considering only P-V work is involved, the total change in enthalpy (in Joule) for the transformation of state in the sequence X→Y→Z is . [Use the given data: Molar heat capacity of the gas for the given temperature range, CV,m = 12 J K-1 mol-1 and gas constant, R = 8.3 J K-1 mol-1]
Answer
8120
Solution
For an ideal gas H depends only on T: H = nCp,m T, with Cp,m = CV,m + R = 12 + 8.3 = 20.3 J K-1 mol-1.
X → Y: T stays 335 K (isothermal) ⇒ H1 = 0.
Y → Z: T rises from 335 K to 415 K, T = 80 K.
H2 = 5 20.3 80 = 8120 J
Htotal = 0 + 8120 = 8120 J
Answer: 8120