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Thermodynamics · Question 3

JEE Advanced 2025 Paper 1NumericalEasy📈 Topic in 17% papers+4
1

Considering ideal gas behavior, the expansion work done (in kJ) when 144 g of water is electrolyzed completely under constant pressure at 300 K is . Use: Universal gas constant (R) = 8.3 J K-1 mol-1 ; Atomic mass (in amu): H = 1, O = 16

Answer

-29.95 to -29.8

Solution

2H2O(l) 2H2(g) + O2(g)

144 g water = 8 mol, which gives 8 mol H2 + 4 mol O2 = 12 mol gas (liquid volume neglected).

w = -P V = - ngRT = -12 8.3 300 = -29880 J = −29.88 kJ

(Work done by the system is 29.88 kJ. The official key accepts −29.95 to −29.8 or 29.8 to 29.95.)

Answer: −29.88

JEE Advanced 2025 Paper 1

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2

Consider the following volume−temperature (V−T) diagram for the expansion of 5 moles of an ideal monoatomic gas. [figure] Considering only P-V work is involved, the total change in enthalpy (in Joule) for the transformation of state in the sequence X→Y→Z is . [Use the given data: Molar heat capacity of the gas for the given temperature range, CV,m = 12 J K-1 mol-1 and gas constant, R = 8.3 J K-1 mol-1]

JEE Advanced 2024 Paper 1

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