The (W/Q) of a Carnot engine is 16, now the temperature of sink is reduced by 62 , then this ratio becomes twice, therefore the initial temperature of the sink and source are respectively
- 33 , 67
- 37 , 99
- 67 , 33
- 97 K, 37 K
Answer
(2) 37 , 99
Solution
= WQ = 1 - T2T1 = 16 ... (i)
After reducing the sink temperature: 1 - T2 - 62T1 = 13 ... (ii)
(ii) - (i): 62T1 = 13 - 16 = 16
T1 = 372 K = 99
From (i): T2 = 56 372 = 310 K = 37
Answer: (2)