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Thermodynamics (Physics) · Question 52

AIPMT 2003MCQEasy📈 Topic in 12% papers+4−1
1

An ideal gas heat engine operates in a Carnot cycle between 227 C and 127 C. It absorbs 6 kcal at the higher temperature. The amount of heat (in kcal) converted into work is equal to

  1. 4.8
  2. 3.5
  3. 1.6
  4. 1.2

Answer

(4) 1.2

Solution

T1 = 227 + 273 = 500 K, T2 = 127 + 273 = 400 K

As per NCERT, efficiency of a Carnot engine: = 1 - T2T1

⇒ = 1 - 400500 = 0.2

⇒ W = Q1 = 0.2 6 = 1.2 kcal

Answer: (4)

AIPMT 2003

Keep practising — Thermodynamics (Physics)

2

The efficiency of Carnot engine is 50\% and temperature of sink is 500 K. If temperature of source is kept constant and its efficiency raised to 60\%, then the required temperature of sink will be

  1. 100 K
  2. 600 K
  3. 400 K
  4. 500 K
AIPMT 2002
3

A scientist says that the efficiency of his heat engine which works at source temperature 127 and sink temperature 27 is 26\%, then

  1. it is impossible
  2. it is possible but less probable
  3. it is quite probable
  4. data are incomplete.
AIPMT 2001
4

The (W/Q) of a Carnot engine is 16, now the temperature of sink is reduced by 62 , then this ratio becomes twice, therefore the initial temperature of the sink and source are respectively

  1. 33 , 67
  2. 37 , 99
  3. 67 , 33
  4. 97 K, 37 K
AIPMT 2000

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