An organic compound undergoes first order decomposition. The time taken for decomposition to ( 18 )th and ( 110 )th of its initial concentration are t1/8 and t1/10 respectively. What is the value of t1/8 t1/10 10? ( 2 = 0.3)
- 30
- 9
- 3
- 0.9
Answer
(2) 9
Solution
For a first order reaction: t = 2.303k [A]0[A]
When the concentration falls to 18 of the initial value: t1/8 = 2.303k 8 = 2.303k 3 2 = 2.303k 0.9
When it falls to 110: t1/10 = 2.303k 10 = 2.303k 1
t1/8 t1/10 = 0.9
t1/8 t1/10 10 = 9
Answer: (2)