The temperature at which the rate constants of the given below two gaseous reactions become equal is K. (Nearest integer) X Y, k1 = 106 e -30000T P Q, k2 = 104 e -24000T Given : 10 = 2.303
Answer
1303
Solution
For k1 = k2:
106 e-30000/T = 104 e-24000/T
106104 = e(30000 - 24000)/T
102 = e6000/T
6000T = 2 10 = 4.606
T = 60004.606 = 1302.6 K 1303 K
Answer: 1303