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Coordination Compounds · Question 96

AIPMT 2001MCQMedium📈 Topic in 25% papers+4−1
1

Which of the following organometallic compounds is and bonded?

  1. [Fe( 5-C5H5)2]
  2. K[PtCl3( 2-C2H4)]
  3. [Co(CO)5NH3]2+
  4. Fe(CH3)3

Answer

(3) [Co(CO)5NH3]2+

Solution

As per NCERT, the metal–carbon bond in metal carbonyls possesses both and character.

CO donates its lone pair on carbon into a vacant metal orbital M–C bond.

A filled metal d orbital donates electrons back into the vacant antibonding * orbital of CO M–C bond (synergic bonding).

The metal carbonyl [Co(CO)5NH3]2+ is the and bonded organometallic compound.

Fe(CH3)3 has only M–C bonds.

Answer: (3)

AIPMT 2001

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2

Which statement is incorrect?

  1. Ni(CO)4 – tetrahedral, paramagnetic
  2. [Ni(CN)4]2- – square planar, diamagnetic
  3. Ni(CO)4 – tetrahedral, diamagnetic
  4. [NiCl4]2- – tetrahedral, paramagnetic.
AIPMT 2001
3

Which of the following will exhibit maximum ionic conductivity?

  1. K4[Fe(CN)6]
  2. [Co(NH3)6]Cl3
  3. [Cu(NH3)4]Cl2
  4. [Ni(CO)4]
AIPMT 2001
4

In qualitative analysis of second group in laboratory, H2S gas is passed in acidic medium for precipitation. When Cu2+ and Cd2+ react with KCN, then for product, true statement is

  1. K2[Cu(CN)4] – more stable; K2[Cd(CN)4] – less stable
  2. K2[Cu(CN)4] – less stable; K2[Cd(CN)4] – more stable
  3. K3[Cu(CN)4] – more stable; K2[Cd(CN)4] – less stable
  4. K3[Cu(CN)4] – less stable; K3[Cd(CN)4] – more stable
AIPMT 2000
5

Shape of Fe(CO)5 is

  1. octahedral
  2. square planar
  3. trigonal bipyramidal
  4. square pyramidal
AIPMT 2000
6

Which complex compound will give four isomers?

  1. [Fe(en)3]Cl3
  2. [Co(en)(NH3)2Cl2]Cl
  3. [Fe(PPh3)3NH3ClBr]Cl
  4. [Co(PPh3)3Cl]Cl3
AIPMT 2000

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