In a vernier callipers, (N+1) divisions of vernier scale coincide with N divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is:
- 110N
- 1100(N+1)
- 100N
- 10(N+1)
Answer
(2) 1100(N+1)
Solution
(N+1) VSD = N MSD
1 VSD = NN+1 MSD
Vernier constant = 1 MSD - 1 VSD = 1N+1 MSD
= 0.1N+1 mm = 0.01N+1 cm
= 1100(N+1) cm
Answer: (2)