Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least division in the M.S. is 0.1 cm and the zero of V.S. is at x = 0.1 cm when the jaws of Vernier callipers are closed. If the main scale reading for the diameter is M = 5 cm and the number of coinciding vernier division is 8, the measured diameter after zero error correction, is
- 4.98 cm
- 5.00 cm
- 5.18 cm
- 5.08 cm
Answer
(1) 4.98 cm
Solution
Least count: LC = 1 MSD - 1 VSD = 0.1 - 910(0.1) = 0.01 cm
Zero error (zero of V.S. to the right of the M.S. zero) = +0.1 cm
Observed reading = 5 + 8 0.01 = 5.08 cm
Corrected diameter = 5.08 - 0.1 = 4.98 cm
Answer: (1)