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The displacement of a particle executing SHM is given by x = 10 ( t + 3 ) m. The time period of motion is 3.14 s. The velocity of the particle at t = 0 is m/s.
10
v = dxdt = 10 ( t + 3 )
= 2 T = 2 3.143.14 = 2 rad s-1
At t = 0: v = 10 2 3 = 20 12
= 10 m/s
Answer: 10
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