The percentage of C, H and N in an organic compound are 40%, 13.3% and 46.7% respectively then empirical formula is
- C3H13N3
- CH2N
- CH4N
- CH6N
Answer
(3) CH4N
Solution
Moles of each element in 100 g of the compound:
⇒ C: 4012 = 3.33
⇒ H: 13.31 = 13.3
⇒ N: 46.714 = 3.33
Dividing by the smallest value (3.33): C : H : N = 1 : 4 : 1
∴ Empirical formula = CH4N
Answer: (3)