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Structure of Atom · Question 56

AIPMT 2002MCQEasy📈 Topic in 0% papers+4−1
1

23592U, nucleus absorbs a neutron and disintegrates into 13954Xe, 9438Sr and x so, what will be product x?

  1. 3-neutrons
  2. 2-neutrons
  3. -particle
  4. -particle

Answer

(1) 3-neutrons

Solution

23592U + 10n 13954Xe + 9438Sr + x

Mass numbers: 235 + 1 = 139 + 94 + A, so A = 3

Atomic numbers: 92 + 0 = 54 + 38 + Z, so Z = 0

x has total A = 3 and Z = 0, i.e. 3 10n (3 neutrons).

Answer: (1)

AIPMT 2002

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2

The following quantum numbers are possible for how many orbitals : n = 3, l = 2, m = +2 ?

  1. 1
  2. 2
  3. 3
  4. 4
AIPMT 2001
3

If a abX species emits first a positron, then two and two particles and in the last, one is also emitted and gets converted to cdY species. So correct relation is

  1. c = a - 12, d = b - 5
  2. c = a - 5, d = b - 1
  3. c = a - 6, d = b - 0
  4. c = a - 4, d = b - 2
AIPMT 2001
4

For given energy, E = 3.03 10-19 Joules corresponding wavelength is (h = 6.626 10-34 J sec, c = 3 108 m/sec)

  1. 65.6 nm
  2. 6.56 nm
  3. 3.4 nm
  4. 656 nm
AIPMT 2000
5

Isoelectronic species are

  1. CO, CN-, NO+, C22-
  2. CO-, CN, NO, C2-
  3. CO+, CN+, NO-, C2
  4. CO, CN, NO, C2
AIPMT 2000

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