Structure of Atom · Question 57

AIPMT 2001MCQEasy📈 Topic in 50% papers+4−1

The following quantum numbers are possible for how many orbitals : n = 3, l = 2, m = +2 ?

Answer

(1) 1

Solution

n = 3, l = 2 ⇒ 3d subshell, which has m = -2, -1, 0, +1, +2 (five orbitals).

⇒ A fixed value of m (m = +2) picks out only one of these orbitals.

∴ The set n = 3, l = 2, m = +2 describes 1 orbital.

Answer: (1)

AIPMT 2001

Keep practising — Structure of Atom

If a abX species emits first a positron, then two and two particles and in the last, one is also emitted and gets converted to cdY species. So correct relation is

c = a - 12, d = b - 5
c = a - 5, d = b - 1
c = a - 6, d = b - 0
c = a - 4, d = b - 2

AIPMT 2001

For given energy, E = 3.03 10-19 Joules corresponding wavelength is (h = 6.626 10-34 J sec, c = 3 108 m/sec)

65.6 nm
6.56 nm
3.4 nm
656 nm

AIPMT 2000

Isoelectronic species are

CO, CN-, NO+, C22-
CO-, CN, NO, C2-
CO+, CN+, NO-, C2
CO, CN, NO, C2

AIPMT 2000

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