An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is 10-1 J. (Take = 3.14) [figure]
Answer
314
Solution
Work done in a cycle = area enclosed by the cycle.
The cycle is a circle with semi-axes:
along P: 500 - 3002 = 100 kPa = 105 Pa
along V: 350 - 1502 = 100 cm3 = 10-4 m3
W = 105 10-4 = 10 = 31.4 J
= 314 10-1 J
Answer: 314