A speeding motorcyclist sees traffic jam ahead of him. He slows down to 36 km hour-1. He finds that traffic has eased and a car moving ahead of him at 18 km hour-1 is honking at a frequency of 1392 Hz. If the speed of sound is 343 m s-1, the frequency of the honk as heard by him will be
- 1332 Hz
- 1372 Hz
- 1412 Hz
- 1454 Hz
Answer
(3) 1412 Hz
Solution
Speed of observer (motorcyclist), vo = 36 km h-1 = 10 m s-1 (moving towards the source)
Speed of source (car), vs = 18 km h-1 = 5 m s-1 (moving away from the observer)
∵ Both move in the same direction with the car ahead,
f' = f ( v + vov + vs )
= 1392 343 + 10343 + 5
= 1392 353348
= 4 353 = 1412 Hz
Answer: (3)