The number of possible natural oscillations of air column in a pipe closed at one end of length 85 cm whose frequencies lie below 1250 Hz are (Velocity of sound = 340 m s-1)
- 4
- 5
- 7
- 6
Answer
(4) 6
Solution
Closed pipe: = (2n - 1)v4L (only odd harmonics)
v4L = 3404 0.85 = 100 Hz
= 100, 300, 500, 700, 900, 1100 Hz (next is 1300 Hz > 1250 Hz)
Number of possible oscillations = 6
Answer: (4)