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If x 1+ (x - 1)(6 + (x - 1)) + (1 - x)(x - 1)3 = -1, where , R, then + is equal to
(3) 18
Put x - 1 = h (h 0+); (1 - x) = - h:
L = h 0+ h(6 + h) - hh3
Use h = 1 - h22 + and h = h - h36 + :
Numerator = (6 + - )h + (- 2 + 6 )h3 +
For a finite limit, 6 + - = 0 = + 6
L = - 2 + 6 = -1
-3 + = -6
-3 + + 6 = -6 = 6, = 12
+ = 18
Answer: (3)
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