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x 0+ (5(x) 13 ) e (1 + 3x2 ) ( -13 x )2 (e5(x) 43 - 1 ) is equal to
(3) 13
As x 0+, use tt 1, e(1 + t)t 1, -1tt 1, et - 1t 1:
(5x 13 ) 5x 13, e(1 + 3x2) 3x2
( -13 x )2 9x, e5x 43 - 1 5x 43
limit = 5x 13 3x29x 5x 43 = 15x 7345x 73
= 13
Answer: (3)
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