Al2O3 is reduced by electrolysis at low potentials and high currents. If 4.0 104 amperes of current is passed through molten Al2O3 for 6 hours, what mass of aluminium is produced? (Assume 100% current efficiency, at. mass of Al = 27 g mol-1).
- 8.1 104 g
- 2.4 105 g
- 1.3 104 g
- 9.0 103 g
Answer
(1) 8.1 104 g
Solution
Al3+ + 3e- Al 3 F deposit 27 g Al
Q = I t
= 4.0 104 6 3600
= 8.64 108 C
Mass of Al = 27 8.64 1083 96500
= 8.06 104 g 8.1 104 g
Answer: (1)