The equilibrium constant of the reaction: Cu(s) + 2Ag+(aq) Cu2+(aq) + 2Ag(s); E = 0.46 V at 298 K is
- 2.0 1010
- 4.0 1010
- 4.0 1015
- 2.4 1010
Answer
(3) 4.0 1015
Solution
Two electrons are transferred: n = 2
At 298 K, K = nE cell0.059
= 2 0.460.059 = 15.6
⇒ K = 1015.6 = 3.98 1015
∴ K 4.0 1015
Answer: (3)