Given : (i) Cu2+ + 2e- Cu, E = 0.337 V (ii) Cu2+ + e- Cu+, E = 0.153 V Electrode potential, E for the reaction, Cu+ + e- Cu, will be
- 0.90 V
- 0.30 V
- 0.38 V
- 0.52 V
Answer
(4) 0.52 V
Solution
Electrode potentials are not additive, but G = - nFE values are.
Required = (i) – (ii):
G3 = G1 - G2
-1 F E3 = -2F(0.337) - [-1F(0.153)]
E3 = 0.674 - 0.153
= 0.521 V 0.52 V
Answer: (4)