A parallel plate air capacitor is charged to a potential difference of V volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates
- increases
- decreases
- does not change
- becomes zero
Answer
(1) increases
Solution
After disconnecting the battery, the charge Q on the plates stays constant (insulating handle).
As per NCERT, C = 0 Ad, so increasing d decreases C.
V = QC = Qd 0 A
V d — the potential difference increases.
Answer: (1)