A rod of linear mass density ' ' and length 'L' is bent to form a ring of radius 'R'. Moment of inertia of ring about any of its diameters is:
- L38 2
- L316 2
- L34 2
- L312
Answer
(1) L38 2
Solution
Mass of the ring: M = L
Circumference = L 2 R = L R = L2
Moment of inertia of a ring about a diameter: I = 12MR2
I = 12( L) ( L2 )2
= L38 2
Answer: (1)