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System of Particles and Rotational Motion · Question 32

JEE Main 2025 (Online) 8th April Evening ShiftMCQEasy📈 Topic in 23% papers+4−1
1

A rod of linear mass density ' ' and length 'L' is bent to form a ring of radius 'R'. Moment of inertia of ring about any of its diameters is:

  1. L38 2
  2. L316 2
  3. L34 2
  4. L312

Answer

(1) L38 2

Solution

Mass of the ring: M = L

Circumference = L 2 R = L R = L2

Moment of inertia of a ring about a diameter: I = 12MR2

I = 12( L) ( L2 )2

= L38 2

Answer: (1)

JEE Main 2025 (Online) 8th April Evening Shift

Keep practising — System of Particles and Rotational Motion

2

A thin solid disk of 1 kg is rotating along its diameter axis at the speed of 1800 rpm. By applying an external torque of 25 N m for 40 s, the speed increases to 2100 rpm. The diameter of the disk is m.

JEE Main 2025 (Online) 8th April Evening Shift
3

A rod of length 5 L is bent at right angle keeping one side length as 2 L. [figure] The position of the centre of mass of the system : (Consider L = 10 cm)

  1. 4 i + 9 j
  2. 2 i + 3 j
  3. 5 i + 8 j
  4. 3 i + 7 j
JEE Main 2025 (Online) 7th April Morning Shift
4

A, B and C are disc, solid sphere and spherical shell respectively with same radii and masses. These masses are placed as shown in figure. [figure] The moment of inertia of the given system about PQ axis is x15I, where I is the moment of inertia of the disc about its diameter. The value of x is .

JEE Main 2025 (Online) 7th April Morning Shift
5

Let M and R be the mass and radius of a disc. A small disc of radius R/3 is removed from the bigger disc as shown in figure. The moment of inertia of remaining part of bigger disc about an axis passing through the centre O and perpendicular to the plane of disc is 4xMR2. The value of x is . [figure]

JEE Main 2025 (Online) 7th April Evening Shift
6

Which of the following are correct expressions for torque acting on a body? ( r = position vector; p = linear momentum; L = angular momentum; = angular acceleration; I = moment of inertia; F = force; t = time) Choose the correct answer from the options given below:

  1. A, B, D and E Only
  2. C and D Only
  3. B, C, D and E Only
  4. B, D and E Only
JEE Main 2025 (Online) 4th April Morning Shift
7

A circular ring and a solid sphere having same radius roll down on an inclined plane from rest without slipping. The ratio of their velocities when reached at the bottom of the plane is x5 where x = .

JEE Main 2025 (Online) 4th April Morning Shift
8

A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is 8 m/s. The speed of the particle on the rim of the wheel at the same level as the centre of the wheel, will be :

  1. 4 2 m/s
  2. 8 m/s
  3. 4 m/s
  4. 8 2 m/s
JEE Main 2025 (Online) 4th April Evening Shift
9

A solid sphere with uniform density and radius R is rotating initially with constant angular velocity ( 1) about its diameter. After some time during the rotation it starts losing mass at a uniform rate, with no change in its shape. The angular velocity of the sphere when its radius becomes R/2 is x 1. The value of x is .

JEE Main 2025 (Online) 4th April Evening Shift
10

A force of 49 N acts tangentially at the highest point of a sphere (solid) of mass 20 kg, kept on a rough horizontal plane. If the sphere rolls without slipping, then the acceleration of the center of the sphere is [figure]

  1. 2.5 m/s2
  2. 3.5 m/s2
  3. 0.25 m/s2
  4. 0.35 m/s2
JEE Main 2025 (Online) 3rd April Morning Shift
11

Moment of inertia of a rod of mass 'M' and length 'L' about an axis passing through its center and normal to its length is ' '. Now the rod is cut into two equal parts and these parts are joined symmetrically to form a cross shape. Moment of inertia of cross about an axis passing through its center and normal to plane containing cross is :

  1. /4
  2. /8
  3. /2
JEE Main 2025 (Online) 2nd April Morning Shift

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