Two simple harmonic motions of angular frequency 100 and 1000 rad s-1 have the same displacement amplitude. The ratio of their maximum acceleration is
- 1 : 103
- 1 : 104
- 1 : 10
- 1 : 102
Answer
(4) 1 : 102
Solution
Maximum acceleration in SHM, amax = 2A
With the same amplitude, a1a2 = 12 22
a1a2 = (100)2(1000)2 = 104106 = 1102
a1 : a2 = 1 : 102
Answer: (4)