The particle executing simple harmonic motion has a kinetic energy K0 2 t. The maximum values of the potential energy and the total energy are respectively
- K0/2 and K0
- K0 and 2K0
- K0 and K0
- 0 and 2K0
Answer
(3) K0 and K0
Solution
Maximum kinetic energy = K0 (when 2 t = 1, at the mean position, where PE = 0).
Total energy E = K0 (constant in SHM).
PE = E - K = K0 - K0 2 t = K0 2 t
Maximum PE = K0 (at the extreme positions)
Answer: (3)