The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is
- 0.707
- zero
- 0.5
Answer
(4) 0.5
Solution
x = A t
v = A t = A ( t + 2 )
a = -A 2 t = A 2 ( t + )
Phase difference between v and a = - 2 = 2 = 0.5
Answer: (4)