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Principles of Inheritance and Variation · Question 107

AIPMT 2008MCQEasy📈 Topic in 50% papers+4−1
1

Which one of the following conditions in humans is correctly matched with its chromosomal abnormality/linkage?

  1. Klinefelter's syndrome — 44 autosomes + XXY
  2. Colour-blindness — Y-linked
  3. Down syndrome — 44 autosomes + XO
  4. Erythroblastosis foetalis — X-linked

Answer

(1) Klinefelter's syndrome — 44 autosomes + XXY

Solution

As per NCERT, Klinefelter's syndrome is caused by an additional X chromosome ⇒ karyotype 47, i.e., 44 autosomes + XXY ⇒ correctly matched.

Colour-blindness is a sex-linked (X-linked) recessive disorder, not Y-linked.

Down syndrome is due to trisomy of chromosome 21 (45 autosomes + XX/XY); 44 autosomes + XO is Turner's syndrome.

Erythroblastosis foetalis results from Rh incompatibility between mother and foetus; it is not X-linked.

∴ Only the first pair is correct.

Answer: (1)

AIPMT 2008

Keep practising — Principles of Inheritance and Variation

2

Haploids are more suitable for mutation studies than the diploids. This is because:

  1. all mutations, whether dominant or recessive are expressed in haploids
  2. mutagens penetrate in haploids more effectively than in diploids
  3. haploids are reproductively more stable than diploids
  4. haploids are more abundant in nature than diploids
AIPMT 2008
3

A human male produces sperms with the genotypes AB, Ab, aB, and ab pertaining to two diallelic characters in equal proportions. What is the corresponding genotype of this person?

  1. AaBb
  2. AABB
  3. AaBB
  4. AABb
AIPMT 2007
4

In pea plants, yellow seeds are dominant to green. If a heterozygous yellow seeded plant is crossed with a green seeded plant, what ratio of yellow and green seeded plants would you expect in F1 generation?

  1. 9 : 1
  2. 3 : 1
  3. 50 : 50
  4. 1 : 3
AIPMT 2007
5

Inheritance of skin colour in humans is an example of:

  1. Chromosomal aberration
  2. Polygenic inheritance
  3. Codominance
  4. Point mutation
AIPMT 2007
6

In the hexaploid wheat, the haploid (n) and basic (x) numbers of chromosomes are:

  1. n = 21 and x = 14
  2. n = 21 and x = 21
  3. n = 7 and x = 21
  4. n = 21 and x = 7
AIPMT 2007
7

A common test to find the genotype of a hybrid is by:-

  1. Crossing of one F1 progeny with recessive parent
  2. Crossing of one F2 progeny with female parent
  3. Crossing of one F2 progeny with male parent
  4. Studying the sexual behaviour of F1 progenies
AIPMT 2007
8

Both sickle cell anemia and Huntington's chorea are-

  1. Congenital disorders
  2. Bacteria-related diseases
  3. Virus-related diseases
  4. Pollutant-induced disorders
AIPMT 2006
9

Test cross involves-

  1. Crossing between two F1 hybrids
  2. Crossing the F1 hybrid with a double recessive genotype
  3. Crossing between two genotypes with recessive trait
  4. Crossing between two genotypes with dominant trait
AIPMT 2006
10

If a colour blind woman marries a normal visioned man, their sons will be

  1. All normal visioned
  2. Three-fourths colourblind and one-fourth normal
  3. One-half colourblind and one-half normal
  4. All colourblind
AIPMT 2006
11

Cri-du-chat syndrome in humans is caused by the-

  1. Loss of half of the long arm of chromosome 5
  2. Loss of half of the short arm of chromosome 5
  3. Trisomy of 21st chromosome
  4. Fertilization of an XX egg by a normal Y-bearing sperm
AIPMT 2006

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