Two radioactive substances A and B of mass numbers 200 and 212 respectively, shows spontaneous -decay with same Q value of 1 MeV. The ratio of energies of -rays produced by A and B is .
- 25482650
- 27062646
- 25972600
- 28622499
Answer
(3) 25972600
Solution
Parent at rest: X Y+ ; momentum conservation p =pY
K= p22m K KY= mYm = A-44
K =Q A-4A
Substance A: K = 196200Q; substance B: K = 208212Q
Ratio = 196 212200 208= 4155241600= 25972600
Answer: (3)