In the given figure R1 = 10 , R2 = 8 , R3 = 4 and R4 = 8 . Battery is ideal with emf 12 V. Equivalent resistance of the circuit and current supplied by battery are respectively : [figure]
- 12 and 11.4 A
- 10.5 and 1.14 A
- 10.5 and 1 A
- 12 and 1 A
Answer
(4) 12 and 1 A
Solution
Top ends of R2, R4, R3 are joined by one wire and their bottom ends by another ⇒ all three are in parallel:
[figure]
1Rp = 18 + 18 + 14 = 12 Rp = 2
Req = 10 + 2 = 12
I = 1212 = 1 A
Answer: (4)