The electric potential at a point in free space due to charge Q coulomb is Q 1011 volts. The electric field at that point is
- 4 0 Q 1020 volt/m
- 12 0 Q 1022 volt/m
- 4 0 Q 1022 volt/m
- 12 0 Q 1020 volt/m
Answer
(3) 4 0 Q 1022 volt/m
Solution
V = Q4 0 r = Q 1011
r = 14 0 1011
E = Q4 0 r2 = Vr
= Q 1011 4 0 1011
= 4 0 Q 1022 volt/m
Answer: (3)