Charges +q and -q are placed at points A and B respectively which are a distance 2L apart, C is the midpoint between A and B. The work done in moving a charge +Q along the semicircle CRD is [figure]
- qQ2 0L
- qQ6 0L
- - qQ6 0L
- qQ4 0L
Answer
(3) - qQ6 0L
Solution
AC = CB = L and B is the centre of the semicircle, so BD = L and AD = 3L.
Potential at C: VC = 14 0 ( qL - qL ) = 0
Potential at D: VD = 14 0 ( q3L - qL ) = - q6 0L
Work done (independent of the path) W = Q(VD - VC)
= - qQ6 0L
Answer: (3)