Consider the general reaction given below at 400 K x A(g) y B(g). The values of Kp and Kc are studied under the same condition of temperature but variation in x and y. (i) Kp = 85.87 and Kc = 2.586 appropriate units (ii) Kp = 0.862 and Kc = 28.62 appropriate units The values of x and y in (i) and (ii) respectively are :
- array|c|c| (i) & (ii) \ 1,2 & 2,1 \ array
- array|c|c| (i) & (ii) \ 1,3 & 2,1 \ array
- array|c|c| (i) & (ii) \ 3,1 & 3,1 \ array
- array|c|c| (i) & (ii) \ 4,1 & 4,1 \ array
Answer
(1) array|c|c| (i) & (ii) \ 1,2 & 2,1 \ array
Solution
Kp = Kc(RT) ng, where ng = y - x
At 400 K: RT = 0.0821 400 = 32.84 (with R in L atm K-1 mol-1)
Case (i): KpKc = 85.872.586 = 33.2 32.84 = (RT)1
ng = +1, i.e. y - x = 1 x = 1, y = 2
Case (ii): KpKc = 0.86228.62 = 0.0301 132.84 = (RT)-1
ng = -1, i.e. y - x = -1 x = 2, y = 1
(i) 1, 2 and (ii) 2, 1
Answer: (1)