On the horizontal surface of a truck a block of mass 1 kg is placed ( = 0.6) and the truck is moving with acceleration 5 m/s2, then the frictional force on the block will be
- 5 N
- 6 N
- 5.88 N
- 8 N
Answer
(1) 5 N
Solution
Limiting friction: fmax = mg = 0.6 1 9.8 = 5.88 N
Force needed to move the block with the truck: ma = 1 5 = 5 N
5 N < 5.88 N the block does not slip; static friction adjusts itself.
Frictional force = ma = 5 N
Answer: (1)