The ratio of the wavelengths of the light absorbed by a Hydrogen atom when it undergoes n = 2 n = 3 and n = 4 n = 6 transitions, respectively, is
- 19
- 14
- 136
- 116
Answer
(2) 14
Solution
1 = RH ( 1n12 - 1n22 )
n = 2 3: 1 1 = RH ( 14 - 19 ) = 5RH36
n = 4 6: 1 2 = RH ( 116 - 136 ) = 5RH144
1 2 = 5RH/1445RH/36 = 36144 = 14
Answer: (2)