The position x of a particle with respect to time t along x-axis is given by x = 9t2 - t3 where x is in metres and t in seconds. What will be the position of this particle when it achieves maximum speed along the +x direction?
- 54 m
- 81 m
- 24 m
- 32 m
Answer
(1) 54 m
Solution
v = dxdt = 18t - 3t2
For maximum v: dvdt = 18 - 6t = 0 ⇒ t = 3 s
(v = 54 - 27 = 27 m s-1, positive ⇒ along +x)
∴ x = 9(3)2 - (3)3 = 81 - 27 = 54 m
Answer: (1)